#include%26lt;stdio.h%26gt;
#include%26lt;conio.h%26gt;
#include%26lt;string.h%26gt;
void main()
{
int i,j,n,t,l,g,sum=0 ;
int b[4][4]={
{1,3,5,7},
{9,11,13,15},
{17,19,21,23},
{25,27,29,31}
};
int m[3][4]={
{2,3,6,7},
{12,13,16,17},
{22,23,26,27},
};
int u[3][4]={
{4,5,6,7},
{14,15,16,17},
{24,25,26,27}
};
int y[3][2]={
{8,9},
{18,19},
{28,29}
};
int x[3][4]= {
{10,11,12,13},
{14,15,16,17},
{18,19,30,31},
};
int z[3][4]= {
{20,21,22,23},
{24,25,26,27},
{28,29,30,31},
};
char name[20];
clrscr();
printf("\n Welcome to mindgame");
printf("\n\n Enter your name:\t");
gets(name);
fflush(stdin);
The above arr of nos should be disp on the screen and a person is asked to think a no from tat arr and if the no is ther he should enter 1 else 0, the output should be the number in his mind!!
Plz suggest me some codes and tell me how to extend the logic till n numbers
I want C codes for mind games using numbers?
Basically when this game is played with a set of cards , the numbers on the cards are arranged in such a way that the first number on the top left hand corner of each card is a power of 2.
The reason for this that any positive integer can be expressed as a sum of the powers of 2. Thus 7 = 4 + 2 + 1 ; 37 = 32 + 4 + 1 ; 41 = 32 + 8 + 1 and so on.
Now , the remaining numbers have to be arranged on each card in such a way that they can be obtained by adding the powers of 2 on the cards in which they are present. For instance the number 15 can be obtained by adding 8 + 4 + 2 + 1. Since these are the powers of 2 which will figure on the top left hand corner of the first four cards , the number 15 has to appear in the first four cards , and in no other card.
Again , suppose we consider 41 ; since 41 = 32 + 8 + 1 , which are the powers of 2 appearing on the first , fourth and sixth cards , 41 should appear only in the first , fourth and sixth cards , not in any other.
basically it comes down to arranging all the numbers in the right cards ; in your program it will be the right arrays.
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