Just for example. How would I get the programme to say:
printf("blah blah");
Then delay here for a set length of time
printf("blah blah blah");
And so on..
How do I use C to program a delay?
on a unix system you would call sleep(seconds);
Reply:Why don't you join one of the hundreds of C forums or user groups where answers to your question will continue for weeks. You will learn far more from these groups than by asking a single question here. That's how I learned to program.
Reply:Here's one way. The time function is found in (at least) DOS, Unix, Win16, Win32, ANSI C, ANSI C++ and OS/2.
Your compiler may offer a better function. For instance, on a DOS, Unix, Win32 or OS/2 system, you could use sleep(), but that's not ANSI C. What I'm offering here uses up a lot of CPU cycles, so it would be OK on an individual PC, but it would not be very acceptable on a multiuser system such as a server.
#define DELAY 4
#include %26lt;time.h%26gt;
#include %26lt;stdio.h%26gt;
int main(void)
{
time_t begin, end;
end = begin = time(NULL);
printf("blah blah");
while ((end - begin) %26lt; DELAY)
{
end = time(NULL);
}
printf("blah blah blah");
return 0;
}
Reply:There is a function in C that works for delaying or sleeping for a certain amount of time....most times, this time is specified in microseconds (i think so...its been long since i used C).
delay( )
The delay( ) function found in dos.h is processor dependent. And it won't work on all
systems. The reason is the delay function is implemented with clock speed.
Simply try writting "delay(400);" It might just work.
Dont forget to include "dos.h", thats the header file for delay function.
Reply:#include%26lt;stdio.h%26gt;
#include%26lt;conio.h%26gt;
#include%26lt;dos.h%26gt;
main()
{
printf("blah blah");
delay(1500);
printf("blah blah blah");
getch();
}
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