C programming question, please help?

Hi, this got to do with command line arguments, the following is my code:





#include %26lt;stdio.h%26gt;





main( int argc, char *argv[] )


{


if( argc %26gt; 5 || argc %26lt; 2){


printf("Usage: spellcheck [-case] [-caps] [dictionary-filename] filename", argv[1]);


exit(2);


}





if(strcmp(argv[2], "-peter") == 0){ *****


printf("Hello world\n");


}





return 0;


}





What's wrong with the **** line here? The program doesn't compile.

C programming question, please help?
What is the error?





But, it looks like you need to include #include %26lt;string.h%26gt; so that the strcmp function can be found.
Reply:== is the equality operator, meaning "the same as". Your code sez: if Object is the same as Zero, when perhaps you mean


if(strcmp(argv[2], '-peter') = 0) {


// ? for false ?





I will just comment, I see a lot of if statements trying to compare Object, when you are testing for state, eg in C++ boolean is a primitive and not an Object (an array is an Object) and therefore, the Object will never equal Zero (or boolean false).





I don't remember if this works in C...


if(strcmp(argv[2], "-peter") = !0{ // not false


if(strcmp(argv[2], "-peter") != 0{ // not sure if this is always true, I think it is.