Outputs to following codes.?

# int x = 1;


if (x %26gt; 3) { if (x %26gt; 4) {


printf ("A"); }


else


{ printf ("B"); } }


else if (x %26lt; 2) {


if (x != 0) {


printf ("C"); } }


printf ("D");





is output "C"?





and also,


int j, k;


for (j = 1; j %26lt;= 4; j = j + 1) {


for (k = 1; k %26lt;= j; k = k + 1)


{ printf ("*"); }


printf ("\n"); }





is output "*"?





and finally,


int g, h;





for (g = 1; g %26lt;= 3; g = g + 1) (could you explain this line and the one after it?)


{


for (h = 0; h %26lt; 3; h = h + 1)


{


if (g == h)


{


printf ("O");


}


else


{


printf ("X");


}


}


printf ("\n");





for (g = 1; g %26lt;= 3; g = g + 1) (could you explain this line ?)

Outputs to following codes.?
First one is: CD


Second one is:


*


**


***


****


Third one is:


XOX


XXO


XXX





for(g=1; g%26lt;=3; g=g+1) is a for statement with the following characteristics:





g=1 assigns the variable g the start value of 1.





g%26lt;=3 is the condition for when the loop will stop (when g is less than or equal to 3 is will still loop. When this condition isn't true...say g=4, the loop terminates).





g=g+1 is incrementing g.





So the loop for g would look something like this if we printed the value of g for each iteration:





g=1


g=2


g=3





the loops with both variables g and h running will look something like this





g=1


h=0


h=1


h=2 //note that the condition in the loop for h is only less than


g=2


h=0


h=1


h=2


g=3


h=0


h=1


h=2
Reply:First Answer is : C D


For Second:


*


* *


* * *


* * * *
Reply:Do your own homework.